Exploring Java Check Point 53 Exception Handling 11
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- If changed to int value = 30;: value is too small Continue after the
- Since o is null, calling any instance method on it (like toString()) will throw a NullPointerException.
- The string s = "abc" has characters at indices 0, 1, and 2. s.charAt(3) attempts to access the 4th character, which does not exist.
- No RuntimeException is thrown. The program prints Infinity.
- Complete
In-Depth Information on Java Check Point 53 Exception Handling 11
method() is called, which attempts to compute 1 / 0. This causes a In main(), method() is called inside a try block. In method(), String s = "abc"; is fine. s.charAt(3) tries to access the 4th character of a ... The array list is declared with 5 elements: list[0] to list[4]. list[5] attempts to access the 6th element, which does not exist. Accessing ... This video tutorial has been taken from Hands-On Object Oriented Programming with
0 The loop doesn't continue to i = 1 because the
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